Quote:
Originally Posted by RatherDashing
I think if you consider both candidates to have an equal shot at winning, then it doesn't change the odds of Crockatt losing either way.
Consider candidate A to be the right choice (the one who ends up with more votes), and candidate B to be the wrong choice. You and your wife don't know if Turner or Locke are candidate A.
So if you put your votes together, there is a 50% chance of having two votes count, and a 50% chance of having no votes count. If you hedge your bets and split the vote, then there is a 100% chance of 1 vote counting. Essentially 100% of 1 vote is equivalent to 50% of 2 votes, since it is considered to be random.
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However if you believe that a 50/50 vote split between Turner and Locke gives Crocket the win than voting for one Candidate gives you a chance of winning whereas splitting your vote guarentees the loss. Now expressed over a large number of people it still will balance out to a 50/50 split and crocket still wins so you are scewed. But at least both voting for one candidate would leave a chance if everyone behaved that way. For example if Crocket has 33% of the vote locked up and NDP gets 2% then all Turner or Locke need to do is have a better than 1% difference in their vote total. If every pair of voters entering agreed to split their vote to try to unseat Crocket than Crocket wins. If you allowed random variation of to equally liked canditates than Crocket loses. So I think the best options are either to not discuss it and vote randomly or vote for the same candidate.