Should be easy for you guys here, but I am completley stuck on this one workquestion. They supply the answer(3.33 ,/s^2) , but not the solution.
I've tried searching online, and asking about everybody I know.
Anways, if anybody here knows how to solve this, I would forever be in your debt.
When an object is dropped from a height of 20.0m above the surface of Planet Z, it will fall 5.00m during the 2nd second of fall.
What is the acceleration of a falling object near the surface of this planet?
The formulas we are given are:
a = (Vf - Vi)/t
d = ([Vf + Vi]/2)t
d = (Vi)t + .5at^2
Vf^2 = Vi^2 + 2ad
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