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View Full Version : 3 way tie for 3rd?


ken0042
09-29-2004, 02:59 PM
OK, so here's a question about tie breakers.

Let's say Calgary wins their last 3 games, and Winnipeg and Sask lose their last 3. It is possible; the only time an of the 3 teams meet is CGY @ WPG.

That would create a 3 way tie. But just like in Rock-Paper-Scissors, the first tie breaker is a draw. Winnipeg beat Sask, Sask beat Calgary, and if Calgary wins @ Winnipeg then Calgary will have the advantage over the Bombers.

And under this scenario it would also mean that Hamilton would win a game, so that would kill the crossover too. (West to East anyways.)

Anybody know how it works?

Resolute 14
09-29-2004, 05:29 PM
Your scenario actually creates a four way tiebreak, as Ottawa would be guaranteed a win to get to 12 points as well. They would have a shot at the crossover from east to west.

Resolute 14
09-29-2004, 05:30 PM
Although, since we are already down 14-0, this discussion is basically moot.

ken0042
09-30-2004, 08:41 AM
Yeah, good on the Stamps to tell me loud and clear not to worry about it.

And if there is a tie with a crossover team, the team doesn't crossover. For a team to crossover, they have to have more points in the standings than the 3rd place team that it replaces.

moon
10-01-2004, 07:47 AM
Originally posted by Snakeeye@Sep 29 2004, 04:29 PM
Your scenario actually creates a four way tiebreak, as Ottawa would be guaranteed a win to get to 12 points as well. They would have a shot at the crossover from east to west.
Ottawa has to beat the fourth place team to cross-over. If the teams are tied the team that is in the conference gets to play. At least I am pretty sure that is how they designed it.